[Android Java] URL 유무 및 추출

Code

//Url만 있는지 없는지 확인, Url만 true, Url + 기타는 false 20221027 LHJ
    public static boolean CheckOnlyUrl(final String requestUrl){
        boolean checkOnlyUrl = false;

        //Url 뽑아내는 작업
        try {
            String REGEX = "[(http(s)?):\\/\\/(www\\.)?a-zA-Z0-9@:%._\\+~#=]{2,256}\\.[a-z]{2,6}\\b([-a-zA-Z0-9@:%_\\+.~#?&//=]*)";
            Pattern p = Pattern.compile(REGEX, Pattern.CASE_INSENSITIVE);
            Matcher m = p.matcher(requestUrl);

            if (m.find()) {
                String host =  m.group();
                requestUrl = requestUrl.replaceAll(host, "").trim();
            }

        } catch (Exception e) {
            e.printStackTrace();
        }

        //Emoji Check
        Pattern rex = Pattern.compile("[\\x{10000}-\\x{10ffff}\ud800-\udfff]");

        //Emoji Check and remove
        Matcher rexMatcher = rex.matcher(requestUrl);
        if(rexMatcher.find()){
            requestUrl = EmojiParser.removeAllEmojis(requestUrl).trim();
        }

        if(requestUrl.length() > 0){
            checkOnlyUrl = false;
        }else {
            checkOnlyUrl = true;
        }

        return checkOnlyUrl;
    }

1. url 유무 체크
2. url이 있으면 true 리턴
3. url이 없으면 false 리턴

 

 

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Reference

https://story.dkserver.wo.tc/entry/JAVA-Android%EC%97%90%EC%84%9C-%EB%AC%B8%EC%9E%90%EC%97%B4%EC%97%90%EC%84%9C-URL%EC%B6%94%EC%B6%9C%ED%95%98%EA%B8%B0-%EC%A0%95%EA%B7%9C%EC%8B%9D

https://jizard.tistory.com/237